(2x-5)(x^2-4x-5)=0

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Solution for (2x-5)(x^2-4x-5)=0 equation: 


Simplifying
(2x + -5)(x2 + -4x + -5) = 0

Reorder the terms:
(-5 + 2x)(x2 + -4x + -5) = 0

Reorder the terms:
(-5 + 2x)(-5 + -4x + x2) = 0

Multiply (-5 + 2x) * (-5 + -4x + x2)
(-5(-5 + -4x + x2) + 2x * (-5 + -4x + x2)) = 0
((-5 * -5 + -4x * -5 + x2 * -5) + 2x * (-5 + -4x + x2)) = 0
((25 + 20x + -5x2) + 2x * (-5 + -4x + x2)) = 0
(25 + 20x + -5x2 + (-5 * 2x + -4x * 2x + x2 * 2x)) = 0
(25 + 20x + -5x2 + (-10x + -8x2 + 2x3)) = 0

Reorder the terms:
(25 + 20x + -10x + -5x2 + -8x2 + 2x3) = 0

Combine like terms: 20x + -10x = 10x
(25 + 10x + -5x2 + -8x2 + 2x3) = 0

Combine like terms: -5x2 + -8x2 = -13x2
(25 + 10x + -13x2 + 2x3) = 0

Solving
25 + 10x + -13x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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